For my enlightenment, why use LATERAL here? I get the same result with a simple CROSS JOIN (though overall I like the clever solution).
Cheers,
Steve
On Thu, Feb 16, 2017 at 12:11 AM, Alessandro Baggi <alessandro.baggi@xxxxxxxxx> wrote:
Il 15/02/2017 19:11, Alessandro Baggi ha scritto:
Il 14/02/2017 21:51, Merlin Moncure ha scritto:Hi Merlin,
On Tue, Feb 14, 2017 at 12:36 PM, Merlin Moncure <mmoncure@xxxxxxxxx>Hi Merlin,
wrote:
On Tue, Feb 14, 2017 at 12:04 PM, Alessandro Baggi
<alessandro.baggi@xxxxxxxxx> wrote:
Hi list,
sorry for my english, I will try to example as well. I've a query
that joins
multiple tables and return a result like:
id,customers,phone,code,number
1 , aaaaaaaa,33333,123 , 2
2 , aassdsds,33322,211 , 1
3 , oooooooo,21221,221 , 1
I need, where "number" field is > 1, to duplicate the row * N(number
field
value) with a result like this:
id,customers,phone,code,number
1 , aaaaaaaa,33333,123 , 2
1 , aaaaaaaa,33333,123 , 2
2 , aassdsds,33322,211 , 1
3 , oooooooo,21221,221 , 1
How I can accomplish to this problem?
SELECT * FROM foo CROSS JOIN LATERAL (1,number);
:-D
oops -- copy/paste error
SELECT * FROM foo CROSS JOIN LATERAL generate_series(1,number);
merlin
.
I've tried your suggested code and with cross join and generate_series I
can generate multiple row. There is a way to put as second args a column
values? I've tried to put "table.number" column values but I got
"generate_series() does not exists". Inserting a simple int like 5 I get
5 results for each row.
I've searched on google but can't find a valid example.
Thanks in advance.
I've solved my problem (passing column as number) using a cast generate_series(1,table.number::int)
thanks to all for answart.
SOLVED
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