Search Postgresql Archives

Re: How does Postgres estimate the memory needed for sorting/aggregating

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

 



On 01/25/2017 09:59 PM, Thomas Kellerer wrote:
There was a question on dba.stackexchange recently:

   http://dba.stackexchange.com/a/162117/1822

That question (and the answer) deals with performance difference of a
query caused by the _declared_ length of a VARCHAR column in SQL Server
(everything else being equal - especially the actual data length)

For the curios: it does make a (big) difference in performance if you
declare varchar(100) or varchar(2000) in SQL Server - something that
really surprised me.

The difference in performance in SQL Servers seems to be caused by SQL
Server's optimizer that uses the _declared_ length of a column to
estimate the memory needed for the aggregation (or sorting).

Now, we all know that there is no performance difference whatsoever for
varchar columns regardless of the declared length.

In one of the comments, to that answer the question was asked how
Postgres knows how much memory it needs to allocate to do the aggregation.

I guess this is based on the column statistics stored in pg_stats, but I
am not sure:


It is based on the average length of values in that column, yes.

We estimate the number of distinct groups produced by the aggregation, and multiply it by average length of the key(s). The declared maximum length of a column does not matter.

So if the grouping is expected to produce 1000 groups, and each key column is 100B on average, 100kB should be enough - but only for the keys. The estimate also has to include the aggregate states, which is a different thing.

>
So here is my question: how does Postgres estimate/know the memory
needed for the aggregation? Or does it dynamically resize the memory if
the initial assumption was wrong?


I'm not sure what you mean by 'dynamically resize'. The above decision is pretty much how planner decides whether to use hash aggregate or group aggregate. If we estimate that the hash aggregate will fit into work_mem, the planner will consider both possibilities. If the estimate says hash aggregate would not fit into work_mem, we'll only consider group aggregate, because that can work with very little memory.

At execution time we'll only use as much memory as actually needed. The trouble is that if we under-estimated the amount of memory, there's no way back.

regards

--
Tomas Vondra                  http://www.2ndQuadrant.com
PostgreSQL Development, 24x7 Support, Remote DBA, Training & Services


--
Sent via pgsql-general mailing list (pgsql-general@xxxxxxxxxxxxxx)
To make changes to your subscription:
http://www.postgresql.org/mailpref/pgsql-general



[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
[Index of Archives]     [Postgresql Jobs]     [Postgresql Admin]     [Postgresql Performance]     [Linux Clusters]     [PHP Home]     [PHP on Windows]     [Kernel Newbies]     [PHP Classes]     [PHP Books]     [PHP Databases]     [Postgresql & PHP]     [Yosemite]
  Powered by Linux