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Re: How to hint 2 coulms IS NOT DISTINCT FROM each other

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> try this :-D

create or replace function indf(anyelement, anyelement) returns anyelement as
$$
  select $1 = $2 or ($1 is null and $2 is null);
$$ language sql;

CREATE VIEW view_circuit_with_status AS (
   SELECT r.*,
          s.circuit_status,
          s.customer_id AS s_customer_id,
          p.line_speed,
          p.customer_id AS p_customer_id
     FROM view_circuit r
     JOIN view_circuit_product_main s
       ON r.circuit_id = s.circuit_id
      AND indf(r.customer_id, s.customer_id)
     JOIN view_circuit_product p
       ON r.circuit_id = p.circuit_id
      AND indf(r.customer_id, s.customer_id)

merlin

This doesn't do much good. This doesn't tell the planner that the 3 customer_ids are actually of same value, and it therefore can't filter them as it sees fit.

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