On 04/01/2016 06:52 AM, arnaud gaboury wrote:
On Fri, Apr 1, 2016 at 3:33 PM, Sándor Daku <daku.sandor@xxxxxxxxx
One of many difficulties with computers that they do what you say
them to do, not what you think or you think you are saying. :)
Lets see:
SELECT d.home_dir
FROM email.mail_dir d, email.mailusers u <- make a join between
mail_dir and mailusers = join every(!) record from the first table
with every(!) record from the second table
WHERE u.username='arnaud.gaboury'; <- but I need only those from the
joined records where the username is arnaud.gaboury
And there, you have it.
You can simply redefine the view.
SELECT *,((mailusers.domain_name || '/'::text) ||
mailusers.username) || '/'::text AS home_dir
FROM email.mailusers;
Thank you so much. This way I get all needed info in one view.
This might help understand what is going on:
http://www.postgresql.org/docs/9.5/interactive/tutorial-join.html
Notice the * after the SELECT statement.
So you have all the data plus the homedir.
You can leave out the whole view thing and incorporate the home_dir
expression right into your select.
Or you can write a function which makes this to you with the usename
as argument.
Regards,
Sándor
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