Search Postgresql Archives

Re: How can I replace the year of the created_at column with the current year dynamically ?

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

 



On 07/02/2014 12:48 AM, Arup Rakshit wrote:



What is the data at your disposal when trying to select the current
year? If it is a timestamp, simply use date_part:
=# select date_part('year', now());
  date_part

-----------
       2014

(1 row)
--
Michael

It is *datetime*. Now my users are created at different date...

say -

user1   24/02/1997
user2 28/02/2011
user3 02/03/2001
user4 01/03/2003
.....

But I have some requirment, where date/month part will be as it is...
but as per the current year, I will replace the actual year with the
current year, while I will be displaying it. To meet this need, I am
currently doing as

select  to_char(created_at,'DD/MM') || '/' || to_char(now(),'YYYY') as
when from users;


Maybe simplify it a bit:

select to_char('2011-01-01'::timestamp,'DD/MM/' || to_char(now(),'YYYY'));

or per Michaels suggestion:

select to_char('2011-01-01'::timestamp,'DD/MM/' || date_part('year', now()));









--
Adrian Klaver
adrian.klaver@xxxxxxxxxxx



[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
[Index of Archives]     [Postgresql Jobs]     [Postgresql Admin]     [Postgresql Performance]     [Linux Clusters]     [PHP Home]     [PHP on Windows]     [Kernel Newbies]     [PHP Classes]     [PHP Books]     [PHP Databases]     [Postgresql & PHP]     [Yosemite]
  Powered by Linux