Hi Arup,
Two ways come to mind for me. They're pretty much the same as Szymon's, just minus the sample table creation. I would suggest creating a view instead, so you can just select from it whenever you please.
create view vw_employee as
select * from employees
where ((age(joining_date::date) like '5 years%') or (age(joining_date::date) like '10 years%') )
or
create view vw_employee as
select * from employees
where
((to_char(joining_date, 'YYYY-MM') = to_char((now() - interval '5 years'), 'YYYY-MM') )
or
(to_char(joining_date, 'YYYY-MM') = to_char((now() - interval '10 years'), 'YYYY-MM')))
And then to check the employees who have completed 5 or 10 years, you'll just do:
select * from vw_employee
This is done off the top of my head so there will likely be syntax errors, but I hope this can give you a general idea.
- Rebecca
On Mon, Jun 30, 2014 at 12:00 PM, Szymon Guz <mabewlun@xxxxxxxxx> wrote:
On 30 June 2014 12:38, Arup Rakshit <aruprakshit@xxxxxxxxxxxxxx> wrote:
I have employee table. Where I have a column joining_date. Now I am looking for a way to get all employee, who completed 5 years, 10 years current month. How to do so ? I am not able to figure this out.Regards,
Arup RakshitHi,take a look at this example:I've created a sample table:
create table users(id serial, joining_date date);
and filled it with sample data:
insert into users(joining_date) select now() - (j::text || 'days' )::interval from generate_series(1,10000) j;Then the query showing up all users who complete 5 and 10 years this month can look like:
with u as (
select id, date_trunc('month', age(now()::date, joining_date)) age
from users
)
select *
from u
where u.age in ('5 years', '10 years');- Szymon
