Jason Long-2 wrote > Can someone suggest the easiest way to compare the results from two > queries to make sure they are identical? First thing that comes to mind: WITH before_qry (col1, col2, col3) AS ( VALUES (1,1,1),(2,2,2),(3,3,3) ) , after_qry (col1, col2, col3) AS ( VALUES (1,1,1),(2,2,2),(3,3,3) ) , before_array AS (SELECT array_agg(before_qry) AS before_agg_array FROM before_qry) , after_array AS (SELECT array_agg(before_qry) AS after_agg_array FROM before_qry) SELECT *, before_agg_array = after_agg_array FROM before_array CROSS JOIN after_array Basically turn the resultsets into arrays (of composites) and then see if the arrays are the same. This has issues with respect to column names and comparable datatypes (i.e., if one column is bigint and the other is integer they still compare equally). One thought would to only allow a view name (and possibly, separately, the ORDER BY clause). Catalog lookups can be used to check for identical view output types. No idea of something like this exists and is readily available. David J. -- View this message in context: http://postgresql.1045698.n5.nabble.com/Easiest-way-to-compare-the-results-of-two-queries-row-by-row-and-column-by-column-tp5760209p5760215.html Sent from the PostgreSQL - general mailing list archive at Nabble.com. -- Sent via pgsql-general mailing list (pgsql-general@xxxxxxxxxxxxxx) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-general