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Re: how to group by similarity ?

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On Wed, Apr 25, 2012 at 8:34 PM,  <hari.fuchs@xxxxxxxxx> wrote:
> Andreas <maps.on@xxxxxxx> writes:
>
>> How would I group the table so that it shows groups that have
>> similarity () > x ?
>>
>> Lets say the table looks like this:
>>
>> id,  txt
>> 1,   aa1
>> 2,   bb1
>> 3,   cc1
>> 4,   bb2
>> 5,   bb3
>> 6,   aa2
>> ...
>>
>> How would a select look like that shows:
>>
>> id,  txt,      group_id
>> 1,   aa1,   1,
>> 6,   aa2,   1,
>> 2,   bb1,   2,
>> 4,   bb2,   2,
>> 5,   bb3,   2,
>> 3,   cc1,   3
>


Hey guys. I have a similar problem and I tried a couple of ways to
solve this including the window function described in the answer to
the original poster in this thread.

The problem I am having is that even with a trigam index and a table
with only 80,000  records the query takes forever to run. In both
cases I ended the query manually and have no idea how long it would
actually take to run. I have included the two queries below and am
hoping somebody can give me a pointer on how to accomplish with a
query that runs.


Query 1

WITH grp (t1, id, t2) AS (
  SELECT t1.raw_data, t1.id, t2.raw_data
  FROM schema.a t1
  LEFT JOIN schema.a t2 ON t2.raw_data > t1.raw_data
  WHERE t2.raw_data IS NULL OR similarity(t1.raw_data, t2.raw_data) > .75
)
SELECT t1, min(id)
FROM (
    SELECT t1, id
    FROM grp
  UNION ALL
    SELECT t2, id
    FROM grp
    WHERE t2 IS NOT NULL
  ) dummy
GROUP BY t1
ORDER BY t1


query 2

select similarity(a.raw_data,b.raw_data),*
from schema.a a, schema.a b where similarity(a.raw_data,b.raw_data) >
.75 and a.id != b.id


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