On 09/01/2012 02:07 PM, Thalis Kalfigkopoulos wrote:
Thanks all for the replies. Actually I had already tested that sum() behaved correctly with respect to NULLs, meaning that it ignored them (or treated them as 0, couldn't really tell). That's why I went ahead sum()ing even though I knew NULLs would always be involved. Unfortunately I didn't see what now seems obvious, that the comparison would be =NULL and not IS NULL.
The main thing to remember is that there are no consistent rules around NULL. Learn each case and don't try to generalize too much.
Think: 1 + 2 + 3 = 6 1 + 2 + NULL = NULL so obviously sum(y) FROM ( VALUES (1),(2),(3) ) x(y) = 6 sum(y) FROM ( VALUES (1),(2),(NULL) ) x(y) = NULL right? No, actually sum() over 1,2,NULL is 3, not NULL. NULL isn't consistent. -- Craig Ringer -- Sent via pgsql-general mailing list (pgsql-general@xxxxxxxxxxxxxx) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-general