On 02/24/12 12:45 PM, amit sehas wrote:
If we have a query of the form: Select *, (Select * FROM T2 WHERE p2 = T1.p1) FROM T1 ORDER BY 1 WHERE p3 = 75
ORDER BY has to be AFTER the WHERE clause. is that query equivalent to... Select t1.*, t2.* FROM T1 LEFT JOIN T2 on T1.p1=t2.p2 WHERE t1.p3 = 75 ORDER 1 ?
In the above query there is a subselect in the target list and the ORDERBY has an ordinal number which indicates order by column 1. Does this mean that the above query will return all results from T1 that match p3 =75 and all results from T2 that match p2 = T1.p1 for every match on T1 and order them all by the first column of T1 and T2 ?
I'm not sure your query as written would even work. if that inner select was to return multiple rows, ugh.
basically i am trying to determine if the order by clause has effect only on the tuples of the outer select or both the outer and inner select. Or the results returned by the inner select are treated as if they are part of a single tuple which includes the tuple from table T1 ?
you can't treat a recordset as a single tuple regardless. the ORDER BY is always done on the data selected by the WHERE
Is this an implementation specific behaviour or it conforms to the SQL standard ...?
I suspect its your proposed query that doesn't conform. -- john r pierce N 37, W 122 santa cruz ca mid-left coast -- Sent via pgsql-general mailing list (pgsql-general@xxxxxxxxxxxxxx) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-general
