On 10 November 2011 15:43, shuaixf <shuaixf@xxxxxxxxx> wrote: > --*Test SQL* > CREATE TABLE tb(id integer primary key, > name varchar(32), > parent integer); > > INSERT INTO tb VALUES(1, 'iPhone', NULL); > INSERT INTO tb VALUES(2, 'HTC', NULL); > INSERT INTO tb VALUES(3, 'Motorola', NULL); > INSERT INTO tb VALUES(4, 'iPhone3GS', 1); > INSERT INTO tb VALUES(5, 'G7', 2); > INSERT INTO tb VALUES(6, 'G8', 2); > INSERT INTO tb VALUES(7, 'iPhone4', 1); > INSERT INTO tb VALUES(8, 'iPhone4-white', 7); > INSERT INTO tb VALUES(9, 'iPhone4-black', 7); > INSERT INTO tb VALUES(10,'G7-A', 5); > INSERT INTO tb VALUES(11,'G7-B', 5); > > *How to create a SQL to inquiry the result like this:* > id name > ---------------- > 1 iPhone > 4 iPhone3GS > 7 iPhone4S > 8 iPhone4S-white > 9 iPhone4S-black > 2 HTC > 5 G7 > 10 G7-A > 11 G7-B > 3 Motorola > > Thank you very much! > > > > > -- > View this message in context: http://postgresql.1045698.n5.nabble.com/How-to-inquiry-a-nest-result-tp4981259p4981259.html > Sent from the PostgreSQL - general mailing list archive at Nabble.com. You can do that with a recursive CTE (common table expression). See the documentation for SELECT in versions 8.4 or later, which contains examples of queries like these. -- If you can't see the forest for the trees, Cut the trees and you'll see there is no forest. -- Sent via pgsql-general mailing list (pgsql-general@xxxxxxxxxxxxxx) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-general
