Tarlika Elisabeth Schmitz, 10.11.2011 00:52:
I would like to implement the equivalent of "count (DISTINCT field) OVER ()":
SELECT
id, name, similarity(name, 'Tooneyvara') as delta,
count (id) OVER() AS cnt
FROM vtown
WHERE
similarity(name, 'Tooneyvara')> 0.1
ORDER BY delta DESC
produces result:
1787 Toomyvara 0.5 4
1787 Toomevara 0.4 4
1700 Ardcroney 0.105 4
1788 Townsfield 0.1 4
What I would like is a "3" in the cnt column (ignoring id duplicates).
This should do it:
SELECT id,
name,
delta,
sum(case when rn = 1 then rn else null end) over() as distinct_id_count
FROM (
SELECT
id, name, similarity(name, 'Tooneyvara') as delta,
row_number() OVER(partition by id) AS rn
FROM vtown
WHERE
similarity(name, 'Tooneyvara') > 0.1
) t
ORDER BY delta DESC
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