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Re: point types in "DISTINCT" queries

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On Wed, 2011-06-29 at 11:37 -0400, Jonathan S. Katz wrote:
> Which means it *should* work, but first I would need to clean up the data and find the duplicates.  I was hoping this might work:
> 
> 	SELECT geocode, count(*)
> 	FROM a
> 	GROUP BY a.geocode
> 	HAVING count(*) > 1;

Maybe you could use a self-join as a workaround for now, just to clean
up the data?

SELECT geocode, other_columns from a a1, a a2 where a1.other_columns <>
a2.other_columns and a1.geocode ~= a2.geocode;

Regards,
	Jeff Davis


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