On Mon, 10 May 2004, Ivan Sergio Borgonovo wrote:
> Now let's come to the problem:
>
> create or replace function testa( )
> returns char(32) as
> '
> begin
> if 1=2 then
> if 1=2 then
> select 1;
> elseif 1=3 then
> select 2;
> elseif 1=4 then
Don't you mean ELSIF, not ELSEIF?
Kris Jurka
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TIP 9: the planner will ignore your desire to choose an index scan if your
joining column's datatypes do not match
