thanks guys for the quick response and tips.
everything works well now. dont know how i didnt catch that one.. :)
- bruce
--- Chadwick Rolfs <cmr@xxxxxxxxxxxxx> wrote:
> Your variables don't match. And your coding is very inconsistent.
> The if
> construct should follow the for construct. It makes everything
> READABLE
> and understandable.
> Good luck
>
> On Sat, 26 Oct 2002, Bruce Young wrote:
>
> > php connection query:
> >
> > <?php
> > #include('DB/pgsql.php');
> >
> > $dbconnect = pg_connect("dbname=campus user=apache");
>
> HERE YOU HAVE DBCONNECT
>
> >
> >
> > $result = pg_exec ($conn, "select * from friends");
>
> HERE YOU HAVE CONN
>
> > if (!result) {printf ("Error\n"); exit;}
> >
> > $numrows = pg_num_rows($result);
> >
> > for ($i=0; $i < $numrows; $i++) {
> > $r = pg_fetch_row($result, $i);
> >
> > for ($j=0; $j < count($r); $j++) {
> > echo "$r[$j] ";
> > }
> > echo "<br>";
> > }
> > pg_close($dbconnect);
> > ?>
> >
> >
> > --- dan radom <dan@xxxxxxxxx> wrote:
> > > * Bruce Young (hbrucey@xxxxxxxxx) wrote:
> > > > my script that does insert works correctly, but i get this
> error
> > > when
> > > > retrieving data:
> > > >
> > > > Warning: pg_exec(): supplied argument is not a valid
> PostgreSQL
> > > link
> > > > resource in /home/httpd/htdocs/view.php on line 115
> > > >
> > > > Warning: pg_num_rows(): supplied argument is not a valid
> > > PostgreSQL
> > > > result resource in /home/httpd/htdocs/view.php on line 118
> > > >
> > >
> > > how about showing us the connection and query parts of view.php
> > >
> > > dan
> > >
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>
> -Chadwick
>
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