I'm having trouble getting an SQL statement to use a variable. Here's the statement: $sql = "SELECT emp_fname FROM employee WHERE username = '$username'"; $result = pg_exec($conn,$sql); if (!$result) { exit; } I get the following warning from this: Warning: Supplied argument is not a valid PostgreSQL link resource in /var/www/personnel/include/functions.inc on line 25 Is there another way to use a variable in an SQL statement. This format works with MySQL. -- Jeff Self Information Technology Analyst Department of Personnel City of Newport News 2400 Washington Ave. Newport News, VA 23607 757-926-6930