On Mon, Nov 3, 2014 at 6:00 PM, Andrew Dunstan <andrew@xxxxxxxxxxxx> wrote:
andrew=# do $x$ declare r abc; begin for i in 1 .. 10000000 loop
select 'a','b',i into r.x,r.y,r.z; end loop; end; $x$;
DO
Time: 63731.434 ms
andrew=# do $x$ declare r abc; begin for i in 1 .. 10000000 loop r
:= ('a','b',i); end loop; end; $x$;
DO
Time: 18744.151 ms
Is it simply because the SELECT is in effect three assignments, so it takes nearly 3 times as long?
I don't think so, because this take pretty much the same time:
SELECT ('a','b',i) INTO r;
SELECT ('a','b',i) INTO r;
Regards,
--
Matheus de Oliveira
Analista de Banco de Dados
Dextra Sistemas - MPS.Br nível F!
www.dextra.com.br/postgres
Analista de Banco de Dados
Dextra Sistemas - MPS.Br nível F!
www.dextra.com.br/postgres
