Re: IN or EXISTS

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On 31/08/2011 4:30 AM, Andy Colson wrote:
Hi all,

I have read things someplace saying not exists was better than not in... or something like that. Not sure if that was for in/exists and not in/not exists, and for a lot of records or not.

`EXISTS' may perform faster than `IN', yes. Using `IN' it is necessary to build a list of values then iterate over them to check for a match. By contrast, `EXISTS' may use a simple index lookup or the like to test for the presence of a value.

On the other hand, the `IN' subquery is uncorrelated needs only run once, where the `EXISTS' subquery is correlated and has to run once for every outer record. That means that the `IN' list approach can be a lot faster where the subquery in question is relatively time consuming for the number of values it returns. For example, if the `IN' query returns only 5 values and takes 100ms, you're scanning 1 million records in the outer query, and the subquery `EXISTS' version would take 50ms, using `IN' is a no-brainer since 1 million times 50ms will be a lot slower than 1 times 100ms plus the time required to scan 5 elements 1 million times.

Another complication is the possible presence of NULL in an IN list. Getting NULLs in `IN' lists is a common source of questions on this list, because people are quite surprised by how it works. EXISTS avoids the NULL handling issue (and in the process demonstrates how woefully inconsistent SQL's handling of NULL really is).

Theoretically the query planner could transform:

SELECT * from y WHERE y.id IN (SELECT DISTINCT z.y_id FROM z WHERE z.y_id IS NOT NULL);

into:

SELECT * FROM y WHERE EXISTS (SELECT 1 FROM z WHERE z.y_id = y.id)

... or vice versa depending on which it thought would be faster. AFAIK it doesn't currently do this. To be able to do it the planner would need to know how to estimate the cost of scanning an `IN' result list. It'd also need to be able to use constraints on the target table to prove that the result of the `IN' may not contain nulls. To transform the EXISTS version into the IN version where it'd be more efficient, it'd also have to be able to use constraints on the target table to prove that results of a SELECT would be unique without explicit deduplication.

All this makes me wonder ... does Pg currently support sorting IN lists and using a binary search? It'd be pretty nice to be able to prove that:

SELECT * from y WHERE y.id IN (SELECT z.y_id FROM z);

is equvalent to:

SELECT * FROM y WHERE y.id IN (SELECT DISTINCT z.y_id FROM z WHERE z_id IS NOT NULL)

... and either transform it to an EXISTS test or add an ORDER BY z_id and flag the resultset as sorted so a binary search could be done on it whenever a row hits the IN test.

--
Craig Ringer

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