On Wed, Mar 23, 2011 at 3:49 PM, Adarsh Sharma <adarsh.sharma@xxxxxxxxxx> wrote:
I can't understand how select 1 from clause2 c where c.source_id = p.crawled_page_id works too, i get my output .Vitalii Tymchyshyn wrote:23.03.11 12:10, Adarsh Sharma ÐÐÐÐÑÐÐ(ÐÐ):I just want to retrieve that id 's from page_content which do not have any entry in clause2 table.Then
select distinct(p.crawled_page_id) from page_content p
Âwhere NOT EXISTS (select 1 from clause2 c where c.source_id = p.crawled_page_id);
is correct query.
What is the significance of 1 here.
Thanks , Adarsh
Best regards, Vitalii Tymchyshyn.
Its the inverted logic for finding crawled_page_id not matching with source_id.
Actually, the idea was to force index scan on clause2 though.
--
Regards,
Chetan Suttraway
EnterpriseDB, TheÂEnterprise PostgreSQLÂcompany.