But if an individual disk fails in a disk array, sooner than later you would want to purchase a new fitting disk, walk/drive to the location of the disk array, replace the broken disk in the array and activate the new disk. Is this correct? Thanks Peter On 4/4/07, Alvaro Herrera <alvherre@xxxxxxxxxxxxxxxxx> wrote:
Andreas Kostyrka escribió: > * Peter Kovacs <maxottovonstirlitz@xxxxxxxxx> [070404 14:40]: > > This may be a silly question but: will not 3 times as many disk drives > > mean 3 times higher probability for disk failure? Also rumor has it > > that SATA drives are more prone to fail than SCSI drivers. More > > failures will result, in turn, in more administration costs. > Actually, the newest research papers show that all discs (be it > desktops, or highend SCSI) have basically the same failure statistics. > > But yes, having 3 times the discs will increase the fault probability. ... of individual disks, which is quite different from failure of a disk array (in case there is one). -- Alvaro Herrera http://www.CommandPrompt.com/ The PostgreSQL Company - Command Prompt, Inc.
