))Hi all, This is my table... <http://postgresql.nabble.com/file/n5855509/screenshot.jpg> This is the SQL statement to create the same table... * CREATE TABLE tbl_ebscbspa_log05 ( pcnum smallint NOT NULL, fnserial serial NOT NULL, fnname character varying NOT NULL, timestmp timestamp without time zone DEFAULT clock_timestamp(), timeelapse interval, timetype character varying, timeindex real, CONSTRAINT table_ebscb_spa_log05_pkey PRIMARY KEY (fnserial) ) WITH ( OIDS=FALSE ); ALTER TABLE tbl_ebscbspa_log05 OWNER TO postgres;* How can I SUM all timeelapse WHERE timetype = 'Break' AND that are placed after(below) the last(descendent) timetype = 'Start'? So in the table above Ill get both blue square colored rows summed up. So I get 'totalbreak' = 00-00-00 02:00:00.000 How would be the syntax to select all possible 'Breaks' after the last(descendent) 'Start' and sum them up? (lets say the max possible 'Breaks' are nine). I have try this, resulting NULL *SELECT t.timeelapse FROM tbl_ebscbspa_log05 t WHERE t.timetype = 'Break' AND NOT EXISTS (SELECT 1 FROM tbl_ebscbspa_log05 WHERE timetype = 'Start' AND 'timestmp' > 't.timestmp') INTO v_timeelapse_break; IF FOUND THEN NEW.timeelapse := v_timeelapse_break;* Pls I would like to know how to SUM THEM UP, not just SELECT THEM, hope some good PostgreSQL fellow programmer could give me a hand with it. Thanks Advanced. -- View this message in context: http://postgresql.nabble.com/SUM-all-timeelapse-WHERE-timetype-Break-but-only-the-rows-that-are-after-below-timetype-Start-tp5855509.html Sent from the PostgreSQL - admin mailing list archive at Nabble.com. -- Sent via pgsql-admin mailing list (pgsql-admin@xxxxxxxxxxxxxx) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-admin
