Re: [PATCH] signal handlers: volatile sigatomic_t, not volatile OR sigatomic_t

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In the case in your example, sleep() doesn't need to be implemented
using SIGALRM. It isn't in glibc and OpenBSD that I know of:
https://sourceware.org/git/?p=glibc.git;a=blob;f=sysdeps/posix/sleep.c;h=3df79097c4464510f0197138a00a0c9772a5e83e;hb=3ab9b88e2ac91062b6d493fe32bd101a55006c6a
https://man.openbsd.org/sleep.3

I managed to make GCC and Clang optimize out a sig_atomic_t store:
```
#define _POSIX_C_SOURCE 200809L

#include <sys/time.h>

#include <stdio.h>
#include <stdlib.h>
#include <signal.h>
#include <string.h>

static void catch_sigalrm(int);

#ifdef VOLATILE
volatile sig_atomic_t msg;
static const char *decl = "volatile sig_atomic_t msg";
#else
sig_atomic_t msg;
static const char *decl = "sig_atomic_t msg";
#endif

volatile sig_atomic_t reply;
volatile sig_atomic_t replied;

int
main(void)
{
	const struct sigaction act = { .sa_handler = catch_sigalrm };
	const struct itimerval timer = {
		.it_value.tv_usec = 1,
		.it_interval.tv_usec = 1,
	};
	sigaction(SIGALRM, &act, NULL);
	setitimer(ITIMER_REAL, &timer, NULL);
	while (!replied) {
		msg = 1;
	}
	printf("%s == %d\n", decl, (int)reply);
}

static void
catch_sigalrm(int unused)
{
	int n = msg;
	if (!n)
		return;
	reply = n;
	replied = 1;
}
```

This runs forever:
```
$ cc -O2 test2.c && ./a.out 
```
This terminates:
```
$ clang -O2 -DVOLATILE test2.c && ./a.out
volatile sig_atomic_t msg == 1
```

Without volatile in its declaration, msg is never set, so the program 
spins forever because the signal handler never tells the loop to stop. 
There's probably a simpler way to do this.

On Wed, Mar 20, 2024 at 07:20:03PM -0400, Elad Lahav wrote:
> Actually, in the example I cited, there are multiple function calls
> (printf, raise) between the two reads. How can the compiler optimize
> out reading the value a second time?
> 
> My view, which is subject to change at any moment and without notice,
> is that you need volatile in the cases where you normally need
> volatile, rather than inherently whenever you use sig_atomic_t. In the
> following example I would not expect you to need it:
> 
> static sig_atomic_t value;
> 
> void
> sig_handler(int signum)
> {
>     value++;
> }
> 
> void
> func(void)
> {
>     value = 0;
>     sleep(1);
>     printf("There have been %d signals while I was napping\n", value);
> }
> 
> --Elad
> 
> On Wed, Mar 20, 2024 at 7:05 PM Elad Lahav <e2lahav@xxxxxxxxx> wrote:
> >
> > No problem...
> > Yes, in your example the issue is that the type is not atomic, and
> > thus subject to partial updates that can be interrupted.
> > Looking at the example given in
> > https://en.cppreference.com/w/c/program/sig_atomic_t the volatile is
> > needed to let the compiler know that the value can be updated in
> > between two reads by the main function. That makes sense, especially
> > if you have code that loops waiting for the value to change.
> >
> > --Elad
> >
> > On Wed, Mar 20, 2024 at 6:39 PM Guilherme Janczak
> > <guilherme.janczak@xxxxxxxxxx> wrote:
> > >
> > > Actually, uh, I misread your reply, forget the previous reply I sent.
> > >
> > > You don't need the volatile with lock-free atomics, but the standard
> > > says you do need it with sig_atomic_t. I don't know of a case that would
> > > break a plain `sig_atomic_t` variable with no `volatile`, however.
> > >
> > > On Wed, Mar 20, 2024 at 04:44:33PM -0400, Elad Lahav wrote:
> > > > Do you really need volatile?
> > > > There are two cases to consider. Either your code synchronizes updates
> > > > to the shared value with the signal handler (e.g., by blocking and
> > > > then unblocking the signal), in which case I believe the compiler
> > > > cannot ignore updates to the value; or you don't, and you can't depend
> > > > on the variable having any specific value in the signal handler. The
> > > > only thing you want to prevent in the latter case is the handler
> > > > observing a partial update to the variable, which I presume is where
> > > > the other requirements originate. (In practice, there should be little
> > > > or no concern with any primitive type on modern hardware).
> > > >
> > > > --Elad
> > > >
> > > > On Wed, Mar 20, 2024 at 4:32 PM Guilherme Janczak
> > > > <guilherme.janczak@xxxxxxxxxx> wrote:
> > > > >
> > > > > Variables shared with signal handlers must be of type `volatile
> > > > > sigatomic_t`, not `volatile` or `sigatomic_t` as the current text says,
> > > > > according to a C11 draft:
> > > > >
> > > > >     When ... interrupted by ... a signal, values of objects that are
> > > > >     neither lock-free atomic objects nor of type volatile sig_atomic_t
> > > > >     are unspecified.
> > > > >
> > > > > Ref: https://www.iso-9899.info/n1570.html#5.1.2.3p5
> > > > > Signed-off-by: Guilherme Janczak <guilherme.janczak@xxxxxxxxxx>
> > > > > ---
> > > > >  memorder/memorder.tex | 4 ++--
> > > > >  1 file changed, 2 insertions(+), 2 deletions(-)
> > > > >
> > > > > diff --git a/memorder/memorder.tex b/memorder/memorder.tex
> > > > > index 5c50d42d..873c3424 100644
> > > > > --- a/memorder/memorder.tex
> > > > > +++ b/memorder/memorder.tex
> > > > > @@ -1317,8 +1317,8 @@ from the viewpoint of the interrupted thread, at least at the
> > > > >  assembly-language level.
> > > > >  However, the C and C++ languages do not define the results of handlers
> > > > >  and interrupted threads sharing plain variables.
> > > > > -Instead, such shared variables must be \co{sig_atomic_t}, lock-free
> > > > > -atomics, or \co{volatile}.
> > > > > +Instead, such shared variables must be \co{volatile sig_atomic_t} or
> > > > > +lock-free atomics.
> > > > >
> > > > >  On the other hand, because the handler executes within the interrupted
> > > > >  thread's context, the memory ordering used to synchronize communication
> > > > > --
> > > > > 2.42.0
> > > > >
> > > > >
> > > >




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