Re: PAM with OpenSSL - urgent help needed

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Hi Thorsten,

Else I can only say I had never problems with that.

thanks for the reply.
The /usr/local/ssl/lib directory contains both libcrypto.so and libcrypto.a
I understand that I'm lacking some basics here, so I renamed the latter to make sure I work with the shared library only.


You said that you used OpenSSL library (or any library for that matter). Did you load it dynamically?
It looks like the problem is that I'm trying to statically load the library by:
gcc -shared mymodule.o -o pam_mymodule.so -L/usr/local/ssl/lib -lcrypto


The PAM Developers Guide refers to statically loaded modules. Does it mean that I have to take the same considerations in case of dynamically loaded module, which in his turn statically load an external library (libcrypto.so in my case)?

I put my module in /ect/pam.d/sshd - I'm not even getting to the pam_sm_authenticate function and the response to the client is always "Access denied".


Thanks again.


----- Original Message ----- From: "Thorsten Kukuk" <kukuk@xxxxxxx>
To: "Pluggable Authentication Modules" <pam-list@xxxxxxxxxx>
Sent: Wednesday, February 02, 2005 2:38 PM
Subject: Re: PAM with OpenSSL - urgent help needed




On Wed, Feb 02, Boris Breslav wrote:

Hi
is there any reason that I should not use OpenSSL library (libcrypto)
with
PAM?
The same piece of code works in a command line program and fails with my
custom PAM module.
I compile the module like this:
gcc -c -fpic -I/usr/local/ssl/include mymodule.c
gcc -shared mymodule.o -o pam_mymodule.so -L/usr/local/ssl/lib -lcrypto

Could it be a problem that /usr/local/ssl/lib/libcrypto.a is a static
library?

Linking a static library into a shared one is always a mistake and should never be made. Else I can only say I had never problems with that.

 Thorsten

--
Thorsten Kukuk         http://www.suse.de/~kukuk/      kukuk@xxxxxxx
SuSE Linux Products GmbH       Maxfeldstr. 5       D-90409 Nuernberg
--------------------------------------------------------------------
Key fingerprint = A368 676B 5E1B 3E46 CFCE  2D97 F8FD 4E23 56C6 FB4B

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