On Sun, Apr 21, 2019 at 06:58:53PM +0300, Dmitry Belyavsky wrote:
> When I use a command
>
> openssl asn1parse -genstr "UTF8String:ф" -out content
>
> I get a 6-byte file. If I understand correctly, it starts with a 2-byte
> header indicating the content length and then contains an encoded letter
> 'ф' I want. But the encoding of it is not UTF8, as the utf8 encoding of a
> cyrillic letter is 2 bytes long.
>
> Am I wrong? If the behavior I see is desired one, how can I convert the
> result of the encoding to UTF8 using openssl internal API?
By default the input string is assumed to contain single-byte octets,
which are individually encoded as UTF-8. This is rarely what you
want if your input is not ASCII. For actual UTF-8 input, you can
use:
$ openssl asn1parse -out content -genstr 'FORMAT:UTF8,UTF8String:Он врет! Он не знает, КАК НАДО!' # [1]
0:d=0 hl=2 l= 53 prim: UTF8STRING :Он врет! Он не знает, КАК НАДО!
The "genstr" format is described in, for example:
https://www.openssl.org/docs/man1.0.2/man3/ASN1_generate_nconf.html
--
Viktor.
[1]. http://www.mnemosyne.ru/homo/galich-6.html
