Hi, Quick answer : as you probably noticed, IV, ciphertext and tag are expected to be distinct buffers. Consequently, ciphertext is just ciphertext (without IV or Tag). Regards, Michel. -----Message d'origine----- De?: openssl-users [mailto:openssl-users-bounces at openssl.org] De la part de c.holper at ades.at Envoy??: mardi 12 juillet 2016 17:48 ??: openssl-users at openssl.org Objet?: [openssl-users] GCM cipher decryption Hi! 2 questions about GCM and the following OpenSSL-Sample please. https://wiki.openssl.org/index.php/EVP_Authenticated_Encryption_and_Decrypti on#Authenticated_Decryption_using_GCM_mode and the function int decrypt(unsigned char *ciphertext, int ciphertext_len, unsigned char *aad, int aad_len, unsigned char *tag, unsigned char *key, unsigned char *iv, unsigned char *plaintext) * Is ciphertext the pure ciperhtext OR is it with IV and TAG still in the string?? * If the 2nd: The IV is expected to be in front of the ciphertext and the TAG is expected to be past of the ciphertext - correct? | IV | ciphertext | TAG | thanks! Christoph -- openssl-users mailing list To unsubscribe: https://mta.openssl.org/mailman/listinfo/openssl-users
