On Wed, 28 Oct 2020 at 16:47, Lars Noodén <lars.nooden@xxxxxxx> wrote:
[...]
> I notice that with -f the $! variable stays blank.
$! is the pid of the last process placed into the background by the
shell's job control. From the shell's perspective, "ssh -f" runs in
the foreground briefly then exits (after forking a copy of itself to
run in the background, but that's not something the shell has
visibility into). Shell job control is not involved, so $! is not
set.
--
Darren Tucker (dtucker at dtucker.net)
GPG key 11EAA6FA / A86E 3E07 5B19 5880 E860 37F4 9357 ECEF 11EA A6FA (new)
Good judgement comes with experience. Unfortunately, the experience
usually comes from bad judgement.
_______________________________________________
openssh-unix-dev mailing list
openssh-unix-dev@xxxxxxxxxxx
https://lists.mindrot.org/mailman/listinfo/openssh-unix-dev
