On Sunday, March 13, 2016, Woody Wu <narkewoody@xxxxxxxxx> wrote:
On Sunday, March 13, 2016, Greg KH <greg@xxxxxxxxx> wrote:On Sat, Mar 12, 2016 at 04:29:08PM +0800, Woody Wu wrote:
> My question is, is there such a kernel parameter to do the job? Probably there
> is a non-parameter solution like passing the initramfs address in a register
> when a boot loader transfer control to the kernel, but this is not an option to
> me since my boot loader (u-boot) does not support doing this. Thanks.
You have the source to your bootloader, I suggest you fix that up to
support this if you want it, not much the kernel can do on it's own
here, sorry.
But the kernel document says,External initramfs images:--------------------------If the kernel has initrd support enabled, an external cpio.gz archive can alsobe passed into a 2.6 kernel in place of an initrd. In this case, the kernelwill autodetect the type (initramfs, not initrd) and extract the external cpioarchive into rootfs before trying to run /init.This has the memory efficiency advantages of initramfs (no ramdisk blockdevice) but the separate packaging of initrd (which is nice if you havenon-GPL code you'd like to run from initramfs, without conflating it withthe GPL licensed Linux kernel binary).It can also be used to supplement the kernel's built-in initramfs image. Thefiles in the external archive will overwrite any conflicting files inthe built-in initramfs archive. Some distributors also prefer to customizea single kernel image with task-specific initramfs images, without recompiling.So I am thinking, can I from my bootloader load a cpio.gz into ram and start kernel with a command line "initrd=0x30000000"? Wii this work? And, in this case should I also pass kernel with someilike "roo=/dev/ram"? Thanks.-woody
I found the initrd=address works! No root= need to be passed. Only let u-boot load a cpio.uboot image into physical memory and set the correct kernel command line, my problem solved. :-)
--
Life is the only flaw in an otherwise perfect nonexistence
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woody
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