On Wed, Jun 17, 2015 at 6:24 PM, Alexander Kuleshov <alex0xax@xxxxxxxxx> wrote:
Ah, I understood, $-1 is just -1 here. But why we push it - 0xffffffffffffffff?
2015-06-17 17:22 GMT+06:00 Alexander Kuleshov <alex0xax@xxxxxxxxx>:
> Hello,
>
> I have a question about interrupt handling in Linux kernel for x86_64.
> As we can read in the
> 64-ia-32-architectures-software-developer-vol-3a-part-1-manual, when
> an interurpt/exception occurs, the handler's stack contains SS, RSP,
> RFLAGS, CS, RIP and error code. My question is: does processor push
> this register on the stack when an interrupt occurs or kernel must
> push it?
>
> In the arch/x86/kernel/entry_64.S we can see following code in the
> idtentry macro:
>
> .ifeq \has_error_code
> pushq_cfi $-1
> .endif
>
> where pushq_cfi is:
>
> .macro pushq_cfi reg
> pushq \reg
> CFI_ADJUST_CFA_OFFSET 8
> .endm
>
> First of all what does it mean $-1 here? I have write simple assembly
> program and I see:
>
> push 0xffffffffffffffff
>
> in the gdb. The second question, if processor pushes error code and
> other during interrupt why we push it here?
>
> Thank you.
Hi
Please don't top post, even replying to yourself :)
IMHO, pushing -1 is to signify this is error code. Later, (just my guess), the error code will be pushed too.
--
regards,
Mulyadi Santosa
Freelance Linux trainer and consultant
blog: the-hydra.blogspot.com
training: mulyaditraining.blogspot.com
Mulyadi Santosa
Freelance Linux trainer and consultant
blog: the-hydra.blogspot.com
training: mulyaditraining.blogspot.com
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