On 29-Jul-2014 5:54 PM, "Anh Le" <anhlq2110@xxxxxxxxx> wrote:
>
> Thanks, Jonathan, for the quick reply.
>
> On Tue, Jul 29, 2014 at 3:36 PM, Jonathan Neuschäfer
> <j.neuschaefer@xxxxxxx> wrote:
> > Which "write operation" is called twice in your scenario?
>
> It's the "write" method of the "struct file_operations" structure. I
> define it like this (no synchronizatin yet):
> static ssize_t sample_write(struct file *f, const char __user *buf,
> size_t len, loff_t *ppos)
> {
> printk(KERN_DEBUG "[sample] buf len: %u, *ppos: %u\n", len, *ppos);
> return simple_write_to_buffer(kbuf, 2048, ppos, buf, len);
> }
>
> > If a userspace program writes 1000 bytes at first, how can you know that
> > it wants to perform another write later on?
>
> I use printk to debug the module. More details in the answer below.
>
> > If a userspace program wants to write a chunk of data atomically, it
> > should use just one call to write(2). (On Linux, one can save some
> > copying by using writev(2), which writes data from multiple buffers in
> > one atomic step.)
>
> I tried the following command: echo $(perl -e "print 'a'x2000") > /dev/sample
> and get the following messages from dmesg:
> [30884.066433] [sample] buf len: 1008, *ppos: 0
> [30884.066451] [sample] buf len: 993, *ppos: 1008
>
> So as I understand my 2001 bytes has been split into 2 chunks, the
Who do you think did this split? I would say write a simple program and do only a single write syscall for your buffer size. Just see if that split happens again.
> first one with 1008 bytes and the second one with 993 bytes, and
> therefore the write operation is called 2 times to consume the whole
> input.
>
> --
> Le Quoc Anh
>
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