2012/8/14 Ezequiel Garcia <elezegarcia@xxxxxxxxx>
Hey wanny,
Yes, and the function is still in the stack!
On Tue, Aug 14, 2012 at 1:04 AM, Mulyadi Santosa
<mulyadi.santosa@xxxxxxxxx> wrote:
> Hi.. :)
>
> On Tue, Aug 14, 2012 at 9:14 AM, 王哲 <wangzhe5004@xxxxxxxxx> wrote:
>> i use the __init for function print_k.
>> in my opinion after the fisrt invoking the print_k in the hello_init.
>> the memory of print_k will be freed,and the second invoking will
>> not be executed.but the result of second invoking is executing .
>>
>> why?
>
> because you're still in module_init.... :)
>
>
On the other hand.. think what would happen if things would work
like you say.
We would have a *very* strange behavior,
and pretty counter-intuitive, don't you think so?
Thank you very much for reply.
as you say,and function is still in the stack,don't be freed
in the memory,what is __init had done? who can give a sample example
to explain the difference existing __init or not?
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