Re: Disabling an interrupt

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Hi Dave,

    I have confirmed the execution has go into
        desc->irq_data.chip->irq_disable(&desc->irq_data);
  However, irq_disable points to kernel/irq/chip.c:default_disable() which do nothings. 
  Unlike default_enable() which called by enable_irq() will unmask the IRQ accordingly.

  I don't understand the reason behind.

BR,
Jacky
	
On 3/3/2011 6:49 AM, Dave Hylands wrote:
Hi Jacky,

Sending to the list as well.

On Tue, Mar 1, 2011 at 1:55 AM, Jacky Lam <lamshuyin@xxxxxxxxx> wrote:
Hi,

    It's long before when I want to enable/disable an interrupt, I call
enable_irq()/disable_irq(). However, recently, I do that again.
disable_irq() do nothing. I looked into the code and find disable_irq()
is pointing to a empty function default_disable(). This change is
started from 2.6.20.

    I want to know what should I do if I want to disable an interrupt now?
So disable/enable_irq are nestable, and you're expected to call them
in the order disable/enable.

You need to call enable_irq exactly the same number of times that you
call disable_irq.

If you start wth inerrtupts enabled and do
enable_irq
...do some stuff...
disable_irq

then disable_irq will do nothing since it just decremented the count
that enable_irq incremented.

Another way of looking at it is that disable_irq increments a count,
and enable_irq decrements a count.
The interrupt is only "really" disabled when the count transitions
from 0 to 1, and the interrupt is only "really" enabled when the count
transitions from 1 to 0.

Dave Hylands


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