Re: BUILD_BUG_ON_ZERO

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

 



Hi Zhang,

On Fri, Feb 25, 2011 at 3:50 AM, Zhang Meng <jammy.linux@xxxxxxxxx> wrote:
> Hi ~List,
>
> Could anybody explain the macro below? what does it mean?
>
> Thanks in advance.
>
> #define BUILD_BUG_ON_ZERO(e) (sizeof(struct { int:-!!(e); }))

This is also known as a compile time assert. I think that this
particular variant has to be used inside a function.

! is just negation and produces a zero or 1 result. !! just does it
twice, so that a non-zero value coming in becomes 1, and a zero value
remains as zero.

If e evaluates to false (zero) then -!!(e) evaluates to zero;
if e evaluates to true (non-zero) then -!!(e) evaluates to -1.

Declaring a bit field with a size of -1 will cause a compiler error.
I'm actually surprised that declaring a bitfield of size 0 works.

The typical declarations of this I've seen usually use arrays and
arrange for the size to be -1 or 1 (which is generally more portable).
When you use the array style declaration, you can use it outside a
function as well.

Dave Hylands

_______________________________________________
Kernelnewbies mailing list
Kernelnewbies@xxxxxxxxxxxxxxxxx
http://lists.kernelnewbies.org/mailman/listinfo/kernelnewbies


[Index of Archives]     [Newbies FAQ]     [Linux Kernel Mentors]     [Linux Kernel Development]     [IETF Annouce]     [Git]     [Networking]     [Security]     [Bugtraq]     [Yosemite]     [MIPS Linux]     [ARM Linux]     [Linux RAID]     [Linux SCSI]     [Linux ACPI]
  Powered by Linux