Hi Dave & Nilesh,
Thanks for your support I fixed it,
Regards,
hemanth
--- On Fri, 24/12/10, Nilesh Tayade <nilesh.tayade@xxxxxxxxxxxx> wrote:
> From: Nilesh Tayade <nilesh.tayade@xxxxxxxxxxxx>
> Subject: Re: copy_to_user
> To: "Dave Hylands" <dhylands@xxxxxxxxx>
> Cc: "Srinivas G." <srinivasg@xxxxxxxxxxxxxxxxxxxxx>, "Dexter Haslem" <dexter.haslem@xxxxxxxxx>, "Hemanth Kumar" <hemwire@xxxxxxxxxxx>, "mukti jain" <muktijn@xxxxxxxxx>, Kernelnewbies@xxxxxxxxxxxxxxxxx
> Date: Friday, 24 December, 2010, 2:50 PM
> On Fri, 2010-12-24 at 01:00 -0800,
> Dave Hylands wrote:
> > Hi Nilesh.
> >
> > On Thu, Dec 23, 2010 at 11:59 PM, Nilesh Tayade
> > <nilesh.tayade@xxxxxxxxxxxx>
> wrote:
> > ...snip...
> > > I tried it, and it seems adding mutex_init()
> works as Mukti mentioned. I
> > > did get a kernel oops before (but no segfault).
> After adding
> > > mutex_init() there is no oops/segfault. The code,
> however, is reading
> > > the garbage, that needs to be fixed.
> >
> > char n[20];
> > short a = *((short *)&n[0]);
> > short b = *((short *)&n[2]);
> > short c = *((short *)&n[4]);
> >
> > This sets a b and c to have essentially random
> values.
> >
> > nbytes = read(
> fd, n, 40);
> >
> > This causes the value of n to change. However, the
> values of a, b, and
> > c retain the same random values you assigned them
> above.
> >
> > printf( "\r a =
> %d \n ", a);
> > printf("\r b =
> %d \n",b);
> > printf("\r c =
> %d \n",c);
> >
> > This prints the random values of a, b, and c rather
> than printing thee
> > values of n that you read in.
>
> Thanks for the explanation Dave.
>
> I did not really bother to debug to avoid the garbage
> values, as the
> main concern was for segfault and kernel oops.
>
> >
> > Dave Hylands
>
>
> --
> Thanks,
> Nilesh
>
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