i am goin through get_current() function as follows:
...........
>>Basically, the task's task_struct and a task's kernel stack occupy an 8KB block that is 8KB aligned, with the task_struct at the beginning and the stack growing from the end downwards. So you can find the task_struct by clearing the bottom 13 bits of the stack pointer value.<<
here how can we say that masking only 13 bits we'll get the address of task_struct?
