Hello list, In "Understanding the Linux kernel" book, it was said that the "size of pid hash table depends on the size of RAM; for example, for the systems having 512MB of RAM, each hash table is stored in 4 page frames and includes 2,048 entries". How is the size of pid hash table determined? I guess the result in the example comes from 512MB/8KB(size of THREAD_INFO) = 2048(entries)*32(bytes) That is say, the size of pid hash table is determined by the maximum number of process which could stored in physical memory. Is it correct? /Adam -- To unsubscribe from this list: send an email with "unsubscribe kernelnewbies" to ecartis@xxxxxxxxxxxx Please read the FAQ at http://kernelnewbies.org/FAQ
