> Hm,from the function's comment: > > /* > *This callback runs from the timer interrupt, and checks > * whether the watchdog thread has hung or not: > */ > > that means,it runs in interrupt context, thus AFAIK it won't > be preempted. Thanks Mulyadi. If I wanted to trace back through the code that got to softlock_tick(), ehat would I look for to find out if pre-emtive switching had been disabled in the kernel source that I have Adrian -- To unsubscribe from this list: send an email with "unsubscribe kernelnewbies" to ecartis@xxxxxxxxxxxx Please read the FAQ at http://kernelnewbies.org/FAQ
