Re: debugging kernel OOPS

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On Wed, Jun 4, 2008 at 6:46 AM, Rajat Jain <Rajat.Jain@xxxxxxxxxxxx> wrote:
> Hi,
>
> The first column is the offset of the code from the begining of the
> function.
>
> The second column is the actual binary instruction present. It is followed
> by corresponding assembly instructions.

Thanks a lot guys .... :-)

>
> Thanks,
>
> Rajat
> ________________________________
> From: kernelnewbies-bounce@xxxxxxxxxxxx on behalf of Manish Katiyar
> Sent: Tue 03-Jun-08 5:47 PM
> To: kernel newbies
> Subject: debugging kernel OOPS
>
> Hi,
>
>   I am reading the following article
> http://kerneltrap.org/Linux/Further_Oops_Insights and the below
> snippet is from there. My question is what are the values
> in first two columns.
> ................
> ...............
>   22:   31 c9                   xor    %ecx,%ecx
>   24:   89 c3                   mov    %eax,%ebx
>   26:   8b 42 08                mov    0x8(%edx),%eax
>   29:   89 f2                   mov    %esi,%edx
>   2b:*  89 43 04                mov    %eax,0x4(%ebx)     <-- trapping
> instruction
>   2e:   89 d8                   mov    %ebx,%eax
>   30:   c7 04 24 0e 00 00 00    movl   [mid=567425]xe,(%esp)
>   37:   e8 85 f0 ff ff          call   0xfffff0c1
> ............
>
> Sorry if the question is too simple, but this is my first time with assembly
> .
>
> --
> Thanks & Regards,
> ********************************************
> Manish Katiyar ( http://mkatiyar.googlepages.com )
> 3rd Floor, Fair Winds Block
> EGL Software Park
> Off Intermediate Ring Road
> Bangalore 560071, India
> ***********************************************
>
> --
> To unsubscribe from this list: send an email with
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>
>



-- 
Thanks & Regards,
********************************************
Manish Katiyar ( http://mkatiyar.googlepages.com )
3rd Floor, Fair Winds Block
EGL Software Park
Off Intermediate Ring Road
Bangalore 560071, India
***********************************************

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