Re: why does it look like linked list traversing misses the head element?

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On Sun, 23 Mar 2008, Manish Katiyar wrote:

> On Sun, Mar 23, 2008 at 12:46 PM, Robert P. J. Day
> <rpjday@xxxxxxxxxxxxxx> wrote:
> >
> >   i'm sure i'm misreading something, but when i look at the macro
> >  definition of "__list_for_each" in list.h:
> >
> >  #define __list_for_each(pos, head) \
> >         for (pos = (head)->next; pos != (head); pos = pos->next)
> >
> >  i could swear that this traversal will visit each node in the list
> >  except for the initial head element.
> >
> >   look closely:  given a starting address of "head", the
> >  initialization starts things off at (head)->next, and continues
> >  traversing as long as pos != head.  so wouldn't this traversal end up
> >  *not* visiting the list element addressed by "head" itself?  or is
> >  that what it's supposed to do?
>
> "Linux kernel development" - Robert Love has a nice detailed
> explaination of it.

ironically, that's the very book i have open in front of me at the
moment and which is confusing me, since robert writes (near the bottom
of p. 347):

"To traverse the list, simply pick an element and follow the pointers
until you get back to the original element.  This removes the need for
a special head pointer."

however, as you explain it, that "sentinel" element *is* a special
kind of head pointer.  so how to explain this discrepancy?

rday
--

========================================================================
Robert P. J. Day
Linux Consulting, Training and Annoying Kernel Pedantry:
    Have classroom, will lecture.

http://crashcourse.ca                          Waterloo, Ontario, CANADA
========================================================================

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