Hi, It might be a very silly question, but I was going through the definition and explaination of container_of macro from the below link http://www.kroah.com/log/linux/container_of.html. However what i understood is that, given a pointer to one of the members of a structure, it would return a pointer to the parent structure. My question is instead of defining container_of as: #define container_of(ptr, type, member) ({ \ const typeof( ((type *)0)->member ) *__mptr = (ptr); (type *)( (char *)__mptr - offsetof(type,member) );}) Why won't this simply work : #define container_of(ptr, type, member) ({ \ (type *)( (char *)(ptr) - offsetof(type,member) );}) Since even after declaring __mptr as member type we are anyway typecasting it to char *. I am sure I must be missing something very silly :-( ... Thanks in advance. -- Thanks & Regards, ******************************************** Manish Katiyar ( http://mkatiyar.googlepages.com ) 3rd Floor, Fair Winds Block EGL Software Park Off Intermediate Ring Road Bangalore 560071, India *********************************************** -- To unsubscribe from this list: send an email with "unsubscribe kernelnewbies" to ecartis@xxxxxxxxxxxx Please read the FAQ at http://kernelnewbies.org/FAQ
