> I did a few simple independent tests between 'char *foo = "foo"' and 'char > foo[] = "foo"' and they confirmed what the KJ docs say, that the latter > results in a smaller object. So I did a test with <fs/partitions/check.c>. I don't know what kind of documentation you've read, but > static char *make_block_name(struct gendisk *disk) > { > - static char *block_str = "block:"; this is the declaration of the variable in the RAM holding address, i.e. pointer; > + static char block_str[] = "block:"; this is the declaration of the memory reference, i.e. address, number, constant. In case of "*const" _optimizing_ compiler *may* not use memory to store the value of the address. So this is not kind of "some doc say", it's pretty much about understanding semantics of the C. ____ -- To unsubscribe from this list: send an email with "unsubscribe kernelnewbies" to ecartis@xxxxxxxxxxxx Please read the FAQ at http://kernelnewbies.org/FAQ