On Tue, 2007-04-03 at 21:51 -0400, John Anthony Kazos Jr. wrote: > > This is wrong. Although the scope is at _block_ level, all variables are > > allocated on the stack at _function_ level. So, when entering func() all > > variables within it, including x and y, are allocated. > > But this doesn't make sense. Why would the compiler not immediately > optimize both variables into the same allocation? It seems obvious to me > that the amount of space pushed onto the stack when the function is > entered should be the maximum space needed by any combination of local > variables in-scope at any time. GCC wouldn't be that stupid, would it? Yes, I agree. But take a look... 00:19:01 framos@core2duo:~ $> more teste.c #include <stdio.h> int main() { { int x=5; printf("x=%d\n",x); printf("addr(x)=%p\n", &x); { int y=10; printf("y=%d\n",y); printf("add(y)=%p\n", &y); } return 0; } 00:19:04 framos@core2duo:~ $> ./teste x=5 addr(x)=0xbf8b0b00 y=10 add(y)=0xbf8b0afc 00:19:06 framos@core2duo:~ $> -- To unsubscribe from this list: send an email with "unsubscribe kernelnewbies" to ecartis@xxxxxxxxxxxx Please read the FAQ at http://kernelnewbies.org/FAQ