--- shivaligupta <shivaligupta308@xxxxxxxxx> wrote: > Mulyadi Santosa wrote: > > >Dear shivaligupta > > > > > > > >>But in the below given example VmSize >> VmLib + > VmExe + VmData > >>+VmStk what does that indicate? > >> > >>bash-2.05b# cat /proc/16108/status > >>Name: thunderbird > >>State: S (sleeping) > >>Tgid: 16108 > >>Pid: 16108 > >>PPid: 4436 > >>TracerPid: 0 > >>Uid: 0 0 0 0 > >>Gid: 0 0 0 0 > >>FDSize: 256 > >>Groups: 0 1 2 3 4 6 10 > >>VmSize: 4156 kB > >>VmLck: 0 kB > >>VmRSS: 4 kB > >>VmData: 108 kB > >>VmStk: 24 kB > >>VmExe: 592 kB > >>VmLib: 1312 kB > >> > >> > > > >As you can see there, VmSize is bigger than the > total. Why? Because > >VmSize represent the size of all allocated VMA. A > size of all VMAs > >doesn't equal to current memory consumption, > because the page might not > >exist there > > > > > Then the page will be in swap space.(plz correct me > if i m wrong) > How can i know how much memory this process has > taken in swap? > I guess that stack and heap will always be in > memory. so is it like > that the memory consumed in swap is because of code > segment + data segment. > > Code pages are not swapped. They have a disk backed-up file, so they are not eligible for swapping. They can be brought into memory from disk, if their pages have been removed, whenever required. Only the data & stack needs swapping. Try also /proc/$PID/statm for getting more memory related information . Cheers ! __________________________________________________ Do You Yahoo!? Tired of spam? Yahoo! Mail has the best spam protection around http://mail.yahoo.com -- Kernelnewbies: Help each other learn about the Linux kernel. Archive: http://mail.nl.linux.org/kernelnewbies/ FAQ: http://kernelnewbies.org/faq/
