On 9/18/05, raja <vnagaraju@xxxxxxxxxxxx> wrote:
> Hi,
> I am writing a module that prints a message when ever a timer issues
> an interrupt.Any way system timer issues an interrupt after 'tick rate'
> and then kernel handles the interrupt handler.But it is not working in
> my module.
> Will you please tell me wht is wrong with it?
For getting an timer interrupt, you can/have to use timer
functionality in the kernel .... When you register your timer, you
will mention a fucntion to be called backed when the timer expires and
that function will be called by the kernel in the timer (soft) irq
context !!!!!!
> My code is as follows
>
>
>
> #define DEVICE_NAME "timer_interrupt"
> #define TIMER_INTERRUPT 8
> static int __init init_timer_interrupt(void);
> static void __exit exit_timer_interrupt(void);
>
> static irqreturn_t timer_interrupt_handler(unsigned int,void *, struct pt_regs *);
>
> int devNo;
> struct file_operations fops = {};
>
> static irqreturn_t timer_interrupt_handler(unsigned int irq,void *data, struct pt_regs *regs)
> {
> printk("Timer Interrup Occured\n");
> return 0;
> }
>
> static int __init init_timer_interrupt()
> {
> printk("Entered Into init_timer\n");
> devNo = register_chrdev(0,DEVICE_NAME,&fops);
> request_irq(TIMER_INTERRUPT,timer_interrupt_handler,SA_SHIRQ,DEVICE_NAME,&devNo);
> printk("Exited From init_timer\n");
> return 0;
> }
>
> static void __exit exit_timer_interrupt()
> {
> printk("Entered Into exit_timer\n");
> unregister_chrdev(devNo,DEVICE_NAME);
> free_irq(TIMER_INTERRUPT,&devNo);
> printk("Exited From exit_timer\n");
> }
>
> module_init(init_timer_interrupt);
> module_exit(exit_timer_interrupt);
>
What you are trying to do in this code ? I don't know why you are
registering your interrupt handler with irq number 8 !!! is this a
timer interrupt ??? if yes then it have to call your function and if
not irq number 8 is a timer interrupt then your function won't be
called as irq 8 might not be used by the kernel or no interrupt
occuring on that irq number !!! (CMIIW)
--
Fawad Lateef
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