On 9/3/05, Thayumanavar Sachithanantham <thayumker@xxxxxxxxx> wrote: > > # you have specified that the 0 - 896 MB of physical RAM being mapped to > 3-4Gb in virtual addr space. How can this be possible, usually a standalone > system will have 256/512 MB of RAM. Can you please make me clear about > this? > I does mean that there exists always a mapping of virtual addresses between > 3-4G to physical addresses which range from 0 to 896 MB(permanent > mapping).In a 256/512 MB < 896 MB, there will be mappings of the virtual > addresses in range 3-4G to the corressponding physical addresses in the > range 0-256/512 MB. > Hope this clears your doubt. > > Thayumanavar. > > I also want to add one thing !!!! the 0 - 896MB physical addresses can be calculated by subracting PAGE_OFFSET(in default (3G/1GG) it is 0xC8000000) from the Virtual Address. So this means that for 512MB System the Virtual addresses for Kernel will be from 3G to 3G + PAGE_OFFSET + 512MB ...... (CMIIW) -- Fawad Lateef -- Kernelnewbies: Help each other learn about the Linux kernel. Archive: http://mail.nl.linux.org/kernelnewbies/ FAQ: http://kernelnewbies.org/faq/
