Hi all, I came accross an inline assembler directive in the kernel code for intel (arch/i386/kernel/process.c): int $0x80\n\t" /* Linux/i386 system call */ I found out, that "int" calls an interrupt routine. In this case, the routine at the address 0x80 in the interrupt vector (I hope, I'm right so far...) The Problem is: Intel says, everything between 32 and 255 are user defined interrupts. Does anyone have an idea, where in my sources I could find the definition of the interrupt vector in order to find out what the code does? Regards, Paul -- GMX DSL = Maximale Leistung zum minimalen Preis! 2000 MB nur 2,99, Flatrate ab 4,99 Euro/Monat: http://www.gmx.net/de/go/dsl -- Kernelnewbies: Help each other learn about the Linux kernel. Archive: http://mail.nl.linux.org/kernelnewbies/ FAQ: http://kernelnewbies.org/faq/
