Thank you for the useful link .
--- Gerardo García Peña <gerardo@xxxxxxxxxxxxxxxx>
wrote:
> Learner wrote:
>
> >Hi,
> >
> > I know this is not the correct place to post this
> >question, but I feel it would be pretty easy for
> the
> >kernel gurus to explain this.
> >
> >TEST CODE
> >==========
> >
> >#include <stdio.h>
> >
> >main()
> >{
> > float a1=1.0;
> > float a2=2.0;
> >
> > printf(" \n");
> > printf(" Size of Float > %d \n", sizeof(float)
> );
> > printf(" Size of Int > %d \n", sizeof(int) );
> > printf(" \n");
> >
> > printf(" CASE 1 : f-f > %f - %f \n\n", a1, a2);
> > printf(" CASE 2 : f-d > %f - %d \n\n", a1, a2);
> > printf(" CASE 3 : d-f > %d - %f \n\n", a1, a2);
> > printf(" CASE 4 : d-d > %d - %d \n\n", a1, a2);
> >}
> >
> >OUTPUT :
> >
> > Size of Float > 4
> > Size of Int > 4
> >
> > CASE 1 : f-f > 1.000000 - 2.000000
> >
> > CASE 2 : f-d > 1.000000 - 0
> >
> > CASE 3 : d-f > 0 - 0.000000
> >
> > CASE 4 : d-d > 0 - 1072693248
> >
> >==================================
> >
> >The CASE1 & CASE2 & CASE4 outputs are expected.
> >
> > Any explanation for CASE3 behaviour.
> > I presume it should behave similar to CASE2 and
> >print 0 - 2.000000 .
> >
> > Could somebody please pin-point what is
> >lacking in my presumtion .
> >
> >Thanks !
> >
> >
> >
> I believe this happens because float is promoted to
> double when it is
> passed as an arg... so you should think that double
> = 8 and int = 4.
>
> I have been googling and I have found this:
>
>
>
http://www-ccs.ucsd.edu/c/function.html#argument%20promotion
>
>
__________________________________
Do you Yahoo!?
Yahoo! Small Business - Try our new resources site!
http://smallbusiness.yahoo.com/resources/
--
Kernelnewbies: Help each other learn about the Linux kernel.
Archive: http://mail.nl.linux.org/kernelnewbies/
FAQ: http://kernelnewbies.org/faq/
