ldt[3] - linux 0.11

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Hi ,

Am a kernel Newbie. I was reading linux 0.11 version code.

I happened to see in INIT_TASK # define

ldt[3] is initialized as

              {0,0}, \
/* ldt */      {0x9f,0xc0fa00}, \
                {0x9f,0xc0f200}, \

First is a NULL segment, how about others being filled with those
values. How was it decided to fill them??
Again these values which are two longs as obtained from des_struct
do not seem to match LDT segment register.

However set_ldt_desc(gdt+FIRST_LDT_ENTRY,&(init_task.task.ldt))
fills up LDT0 etc. appropriately with the base as &init_task.task.ldt

Really confusing of where and how these values "0x9f,0xc0fa00"
                                              "0x9f,0xc0f200"
are used.

Please help me out in understanding the same.

Thanks in advance,
Sudharsan.




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