On Thu, Oct 21, 2004 at 16:40:14 -0700, Can Sar wrote: > Hi, > > I am making some modifications to the Linux sys_open function to keep > track of various things. Two of the things I am trying to do is to get > the path of the executable that is doing the open, and the path of the > file being opened. > Let me start with the file name: I have tried to copy the path from the > user (it is stored by) filename using strncpy_from_user into a buffer > of size PATH_MAX, and also tried to strcpy tmp, which is what > getname(filename) returns (a kernel pointer). Every time I try to copy > this though, my kernel just crashes. My theory is that it is missing a > '\0' but I am not really sure. Can someone help? Theories are worthless. Could you describe HOW the kernel crashes? Anyway, the best way is to get user-mode-linux, attach debugger to it... > My other problem is figuring out where to get the path for exec from, > is there someway to find this using current? I've been looking through > several files, but couldn't figure out a way. Have a look at how the /proc entries are generated. They include symlink to the executable, so there has to be a code that get's the path. ------------------------------------------------------------------------------- Jan 'Bulb' Hudec <bulb@xxxxxx>
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