I think there's no error in this text (I haven't read it all). But each process has a different adress space (4GB each). In these 4GB, 3 are for the user space and 1GB for the kernel (for the stuff that the process do in kernel space).Thanks a lot for the information! I get the idea of 1GB physical RAM mapped to 1GB virtual memory for kernel from this link: http://kerneltrap.org/node/view/2450 I guess it's just wrong.
But you have to understand for each process, for example the adress 0x4565 is mapped (or can be mapped) to a different physical adress. This is done by using different page table.
And don't confuse kernel and kernel space.
-- Kernelnewbies: Help each other learn about the Linux kernel. Archive: http://mail.nl.linux.org/kernelnewbies/ FAQ: http://kernelnewbies.org/faq/
