In the schedule() function, there is this line:
if (prev->state && !(preempt_count() & PREEMPT_ACTIVE)) {
I wonder why the right part is needed.
PREEMPT_ACTIVE is defined to 0x4000000,
so, even if preempt_count() return 0,1,2,.. it will always be 0 when we do the
logical AND with 0x4000000. So !0 become true, therefore the right side is
always true. Maybe am I missing something?
TIA
--
Kernelnewbies: Help each other learn about the Linux kernel.
Archive: http://mail.nl.linux.org/kernelnewbies/
FAQ: http://kernelnewbies.org/faq/
